-x^2+63x+33=6x^2+16x+19

Solution for -x^2+63x+33=6x^2+16x+19 equation:

-x^2+63x+33=6x^2+16x+19

We move all terms to the left:

-x^2+63x+33-(6x^2+16x+19)=0

We add all the numbers together, and all the variables

-1x^2+63x-(6x^2+16x+19)+33=0

We get rid of parentheses

-1x^2-6x^2+63x-16x-19+33=0

We add all the numbers together, and all the variables

-7x^2+47x+14=0

a = -7; b = 47; c = +14;
Δ = b2-4ac
Δ = 472-4·(-7)·14
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-51}{2*-7}=\frac{-98}{-14}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+51}{2*-7}=\frac{4}{-14}
=-2/7
$